JSSC ANM Recruitment 2019 Apply Online (1985 Vacancies Opening)
JSSC ANM Vacancy 2019: Advertisement of Jharkhand A.N.M Competitive Examination 2019-20 Regular and Backlog Recruitment notification has been released recently. Government of Jharkhand, Jharkhand Staff Selection Commission (JSSC) invites online application from eligible Nursing / ANM qualified candidates for the total vacancy of 1985 to be filled through JSSC ANM Competitive Examination.
The last date for registration of online applications is 29th September 2019.
Jharkhand JSSC JANMCE 2019 Examination:
|Name of the Post||Total Vacancies|
Age Limit: Minimum – 18 years; Maximum – 38 years for General and 40 years for Reserved categories.
Pay Scale: ₹ 5200 – 20200 + Grade Pay ₹ 2400/-
Educational Qualification: Minimum 10th class (Matriculation) Pass with minimum 45% marks. Candidates should have passed Auxiliary Nurse Midwife (ANM) certification.
Application Fee: ₹ 1200/- for General (OC) and OBC category candidates; ₹ 300/- for Reserved category candidates. The fee should be made through online payment mode using Net-banking/ Credit or Debit Card. No fee for PWD / Physically challenged candidates.
Selection Process: JANMCE 2019 Competitive Examination
How to Apply: Online Application Form For JANMCE-2019 available at JSSC Official website. The online registration will be made through jssc.cbtexam.in on or before 04/10/2019.
Help Desk: For any queries / clarification contact phone Number – 9453827207, 9455874494 (OR) email to firstname.lastname@example.org.
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